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In parallelogram abcd ab^2 + bc^2= 260 and ac=18 then what is bd? - Quora
In parallelogram abcd ab^2 + bc^2= 260 and ac=18 then what is bd? - Quora

In ∆ABC, if AD is the median, then show that AB2+AC2 = 2(AD2+BD2) Please give a easy method of solving - Brainly.in
In ∆ABC, if AD is the median, then show that AB2+AC2 = 2(AD2+BD2) Please give a easy method of solving - Brainly.in

in a Triangle ABC, AD perpendicular to BC then prove that AB2 + CD2 =AC2 + BD2[tex] {ab }^{2} + - Brainly.in
in a Triangle ABC, AD perpendicular to BC then prove that AB2 + CD2 =AC2 + BD2[tex] {ab }^{2} + - Brainly.in

In ABC, AD is a median, hence according to the Apollonius theorem, ............ is true.
In ABC, AD is a median, hence according to the Apollonius theorem, ............ is true.

In triangle ABC, ad is perpendicular to bc and ad^2=bd×cd. How do you prove that ab^2+AC^2 = (bd+cd) ^2? - Quora
In triangle ABC, ad is perpendicular to bc and ad^2=bd×cd. How do you prove that ab^2+AC^2 = (bd+cd) ^2? - Quora

In ABC , if AD is the median, show that AB^2 + AC^2 = 2(AD^2 + BD^2) .
In ABC , if AD is the median, show that AB^2 + AC^2 = 2(AD^2 + BD^2) .

Ex 6.6, 3 (Optional) - ABC is a triangle in which angle ABC > 90, AD
Ex 6.6, 3 (Optional) - ABC is a triangle in which angle ABC > 90, AD

Ex 6.6, 4 (Optional) - ABC is a triangle, ABC < 90. Prove AC2 = AB2
Ex 6.6, 4 (Optional) - ABC is a triangle, ABC < 90. Prove AC2 = AB2

In triangle ABC, AD is a median Prove that AB2 + AC2 = 2(AD2 + BD2) - Maths - Triangles - 1179767 | Meritnation.com
In triangle ABC, AD is a median Prove that AB2 + AC2 = 2(AD2 + BD2) - Maths - Triangles - 1179767 | Meritnation.com

Prove that AC2 = AD2 + 3CD2. OLD_Pythagoras Theorem-Maths-Class-9
Prove that AC2 = AD2 + 3CD2. OLD_Pythagoras Theorem-Maths-Class-9

ABCD` is a parallelogram Fig. 2 (c ) .64. AC` and (BD) are its diagonals. Show that ` - YouTube
ABCD` is a parallelogram Fig. 2 (c ) .64. AC` and (BD) are its diagonals. Show that ` - YouTube

In a triangle ABC, AD is perpendicular to BC, prove that AB^2+CD^2=AC^2+BD^2? - Quora
In a triangle ABC, AD is perpendicular to BC, prove that AB^2+CD^2=AC^2+BD^2? - Quora

In ∆ABC, if AD is the median, then show that AB^2+AC^2 = 2(AD^2+BD^2). - Sarthaks eConnect | Largest Online Education Community
In ∆ABC, if AD is the median, then show that AB^2+AC^2 = 2(AD^2+BD^2). - Sarthaks eConnect | Largest Online Education Community

In ABC , if AD is the median, then show that AB^2 + AC^2 = 2(AD^2 + BD^2)
In ABC , if AD is the median, then show that AB^2 + AC^2 = 2(AD^2 + BD^2)

In Fig., ABD is a triangle right angled at A and AC BD. Show that:(i) AB^2 = BC . BD (ii) AC^2 = BC . DC (iii) AD^2 = BD . CD
In Fig., ABD is a triangle right angled at A and AC BD. Show that:(i) AB^2 = BC . BD (ii) AC^2 = BC . DC (iii) AD^2 = BD . CD

Ex 6.5, 3 - ABD is a triangle right angled at A & AC ⊥ BD
Ex 6.5, 3 - ABD is a triangle right angled at A & AC ⊥ BD

In any triangle ABC, prove that AB^2 + AC^2 = 2(AD^2 + BD^2) , where D is the midpoint of BC.
In any triangle ABC, prove that AB^2 + AC^2 = 2(AD^2 + BD^2) , where D is the midpoint of BC.

In ABC, if AD is the median, show that AB^2 + AC^2 = 2(AD^2 + BD^2)
In ABC, if AD is the median, show that AB^2 + AC^2 = 2(AD^2 + BD^2)

In the given figure, AD BC , Prove that AB^2 + CD^2 = BD^2 + AC^2
In the given figure, AD BC , Prove that AB^2 + CD^2 = BD^2 + AC^2

ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB² = BC.BD ( ii) AC² = BC.DC (iii) AD² = BD.CD
ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB² = BC.BD ( ii) AC² = BC.DC (iii) AD² = BD.CD

In triangle ABC, AD is median Prove that AB2 + AC2 = 2AD2 + 2DC2 - Maths - Triangles - 1205046 | Meritnation.com
In triangle ABC, AD is median Prove that AB2 + AC2 = 2AD2 + 2DC2 - Maths - Triangles - 1205046 | Meritnation.com

geometry - To prove in a triangle: $AD^2=AB\cdot AC- BD\cdot CD$ - Mathematics Stack Exchange
geometry - To prove in a triangle: $AD^2=AB\cdot AC- BD\cdot CD$ - Mathematics Stack Exchange

Solved Q2/ In the triangle ABC let D be the midpoint of BC | Chegg.com
Solved Q2/ In the triangle ABC let D be the midpoint of BC | Chegg.com

If AD ⊥ BC, prove that AB 2+ CD 2= B D 2+ AC 2. [2 MARKS]
If AD ⊥ BC, prove that AB 2+ CD 2= B D 2+ AC 2. [2 MARKS]

In a Quadrilateral ABCD, AB+BC+CD+DA is Less Than 2(AC+BD) || C.B.S.E. Grade 7 Mathematics - YouTube
In a Quadrilateral ABCD, AB+BC+CD+DA is Less Than 2(AC+BD) || C.B.S.E. Grade 7 Mathematics - YouTube

In the given Fig., AD ⊥ BC. Prove that AB2 + CD2 = BD2 + AC2. from Mathematics Triangles Class 10 CBSE
In the given Fig., AD ⊥ BC. Prove that AB2 + CD2 = BD2 + AC2. from Mathematics Triangles Class 10 CBSE